Question 666785
g(x) = {{{1/(x^2 - 7x + 10)}}}
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The denominator cannot be zero, so find domain limitations by setting the denominator equal to 0.
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{{{x^2 - 7x + 10 = 0}}}
(x-2)(x-5) = 0
x-2=0, so x = 2
x-5=0, so x = 5
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Basically, x cannot equal these 2 or 5, so the domain is 
all values <2, between 3 and 4, and >5.
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Domain
(-{{{infinity}}}, 1) and (3, 4) and (6, {{{infinity}}})
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