Question 666158
Starting with
h(x) = {{{1/(6-sqrt(x-2))}}}
...
Domain limited to where 0 is in the denominator or a negative is under the square root.
{{{6-sqrt(x-2) > 0}}}
{{{6 < sqrt(x-2)}}}
...
{{{6^2 < sqrt(x-2)^2}}}
{{{36 < x-2}}}
{{{36 + 2 < x}}}
{{{x > 38}}}
...
Domain is all {{{x > 38}}}
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