Question 669134
In 1995, 70% of all children in the U.S. were living with both parents. If 25 children were selected at random in the U.S., what is the probability that at least 15 of them will be living with both of their parents? Round your answer to 4 decimal places.
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Binomial Problem with n = 25 ; p(living with) = 0.7 ; p(not liv with) = 0.3
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P(15 <= x <= 25) = 1 - binomcdf(25,0.7,14) = 0.9022
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Cheers,
Stan H.
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