Question 669257
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ \int_0^3\,-\frac{dx}{x\ +\ 4}\ =\ \left\ -\ln(x\ +\ 4)\right|_0^3\ =\ -\left(\ln(7)\ -\ \ln(4)\right)]


The rest is just a little calculator work.  And, yes, the area IS negative.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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