Question 669084
A box contains 23 yellow, 30 green and 31 red jelly beans.
If 14 jelly beans are selected at random, what is the probability that:
a)   12 are yellow?
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I assume you mean EXACTLY 12 yellow and EXACTLY 2 non-yellow ones

{{{("C(23,12)"*"C(61,2)")/"C(84,14)"}}} = .0000007796187072
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b)   12 are yellow and 1 are green?
<pre>
I assume you mean EXACTLY 12 yellow, EXACTLY 1 green and 
EXACTLY 1 red

{{{("C(23,12)"*"C(30,1)"*"C(31,1)")/"C(84,14)"}}} = .0000003352458754
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c)   At least one is yellow?
<pre>
We calculate the probability of the complement event, that none are
yellow, and subtract from 1:

1 - {{{"C(61,14)"/"C(84,14)"}}} =.9929065388

Edwin</pre>