Question 669201
difference of two natural no. are 4 and the sum of their square is 58 what the number
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Equations:
x - y = 4
x^2 + y^2 = 58
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Substitute for "x" and solve for "y":
(4+y)^2 + y^2 = 58
16 + 8y + 2y^2 = 58
y^2 + 4y -21 = 0
(y+7)(y-3) = 0
Natural Number solution:
 y = 3
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Solve for "x"
x = 4+y
x = 7
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Cheers,
Stan H.
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