Question 669156
x1		y1	x2	y2									
-2		-6	-5	-8									
													
slope m =		(y2-y1)/(x2-x1)											
(	-8	-	(-6)	)/(	-5	-	(-2)	)					
(	-2	/	-3	)  									
m=		 2/3						 					
The required line passes through both the points. So we select one point and plug it with the slope 													
Plug value of  the slope  and point(-2,	-6) in						
Y	=	m	x	+	b								
-6.00	=	 2/3	*	-2	+	b							
-6.00	=	-1 1/3	+	b									
b=	-6    	+	4/3										
b=	-14/ 3												
So the equation  will be													
Y 	=	 2/3	x	-14/3								
m.ananth@hotmail.ca