Question 669128

h(x)=sqroot(-5x-5)


h(x) = {{{sqrt(- 5x - 5)}}}


y = {{{sqrt(- 5x - 5)}}}


0 = {{{sqrt(- 5x - 5)}}}


{{{0^2 = - 5x - 5}}} ------ Squaring each side


0 = - 5x - 5


5x = - 5


{{{x = (- 5)/5}}}, or {{{highlight_green(- 1)}}}


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