Question 669143
Complete the square
{{{u^2 + 2u - 2 = 0}}}
{{{u^2 + 2u + 1 = 2 + 1}}}
(u+1)(u+1) = 3
{{{sqrt(u+1)^2}}} = +- {{{sqrt(3)}}}
{{{u + 1}}} = +- {{{sqrt(3)}}}
{{{u = -1 +- sqrt(3)}}}
...
solutions
{{{-1+sqrt(3) and -1 - sqrt(3)}}}
.....
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