Question 669143
Use the quadratic formula to solve for 'u'


{{{u = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{u = (-(2)+-sqrt((2)^2-4(1)(-2)))/(2(1))}}}


{{{u = (-2+-sqrt(4-(-8)))/(2)}}}


{{{u = (-2+-sqrt(4+8))/(2)}}}


{{{u = (-2+-sqrt(12))/2}}}


{{{u = (-2+sqrt(12))/2}}} or {{{u = (-2-sqrt(12))/2}}}


{{{u = (-2+2*sqrt(3))/2}}} or {{{u = (-2-2*sqrt(3))/2}}}


{{{u = -1+sqrt(3)}}} or {{{u = -1-sqrt(3)}}}


So the exact solutions are {{{u = -1+sqrt(3)}}} or {{{u = -1-sqrt(3)}}}