Question 668932
Since you get to choose your own, work backward and pick simple roots.
Lets say, 2 and 4
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(x-2)(x-4) : which is the factored form
Therefore, the equation is: {{{x^2 - 6x + 8 = 0}}}
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Completing the square
{{{x^2 - 6x + 9 = -8 + 9}}}
(x-3)(x-3) = 1
{{{(x-3)^2 = 1}}}
{{{sqrt(x-3)^2 = +-sqrt(1)}}}
{{{x - 3 = +-sqrt(1)}}}
{{{x = 3 +- sqrt(1)}}}
x = 3+1 = 4
x = 3-1 = 2
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Quadratic formula
*[invoke solve_quadratic_equation 1, -6, 8]
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