Question 668957
{{{-2x^2 - 5x + 5 = 0}}}


{{{2x^2 + 5x - 5 = 0}}}


Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(5)+-sqrt((5)^2-4(2)(-5)))/(2(2))}}}


{{{x = (-5+-sqrt(25-(-40)))/(4)}}}


{{{x = (-5+-sqrt(25+40))/(4)}}}


{{{x = (-5+-sqrt(65))/4}}}


{{{x = (-5+sqrt(65))/4}}} or {{{x = (-5-sqrt(65))/4}}}


So the exact solutions are {{{x = (-5+sqrt(65))/4}}} or {{{x = (-5-sqrt(65))/4}}}