Question 668998
{{{expr(1/2)x^2-x+5=0}}}


{{{2*(expr(1/2)x^2-x+5)=2*0}}}


{{{x^2-2x+10=0}}}


Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(-2)+-sqrt((-2)^2-4(1)(10)))/(2(1))}}}


{{{x = (2+-sqrt(4-(40)))/(2)}}}


{{{x = (2+-sqrt(-36))/2}}}


{{{x = (2+sqrt(-36))/2}}} or {{{x = (2-sqrt(-36))/2}}}


{{{x = (2+6*i)/2}}} or {{{x = (2-6*i)/2}}}


{{{x = 1+3i}}} or {{{x = 1-3i}}}


So the two solutions are {{{x = 1+3i}}} or {{{x = 1-3i}}}


For some strange reason, the book isn't showing the full simplified answers. The answer of those choices given is {{{x = 1+sqrt(9)*i}}} or {{{x = 1-sqrt(9)*i}}} (so either A or C -- Note: the 'i' term is NOT in the square root)


Why the book did not simplify the square root of 9, I have no clue.