Question 668891
{{{y>2abs(x+3)-3}}}

since the solution for {{{abs(x+3)}}} is equal to {{{x+3}}} or {{{x+3}}}, we have

{{{y>2(x+3)-3}}}

{{{y>2x+6-3}}}

{{{y>2x+3}}}.....set {{{y=0}}} and solve for {{{x}}}

{{{0>2x+3}}}....=>....{{{-3>2x}}}.=>....{{{-3/2>x}}} or {{{x<-3/2=-1.5}}}


or, if {{{y>2(-(x+3))-3}}}

{{{y>2(-x-3)-3}}}

{{{y>-2x-6-3}}}

{{{0>-2x-9}}}

{{{2x>-9}}}

{{{x>-9/2}}}

{{{x>-4.5}}}



solution interval: {{{y>2abs(x+3)-3}}} is defined for *[tex \LARGE \{\forall\,x\,|\,x\,\in\,\mathbb{R}\,and\,\-4.5<x<-1.5\}]



{{{ graph( 600, 600, -10, 10, -10, 10, y>2abs(x+3)-3) }}}