Question 668740
FACT: All imaginary roots come in conjugate pairs.

So we have 2,-i,i, -6+i, -6-i.

Then (x-2)[(x+i)(x-i)][(x-(-6+i))(x-(-6-i))] = (x-2)(x^2+1)(x^2+12x+37) = x^5+10x^4+14x^3-64x^2+13x-74