Question 668702
6x^2-x-35 = 0 (don't forget = 0)
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(2x-5)(3x+7) = 0
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Check with FOIL {{{cartoon(
(2x-5)(3x+7),
(highlight(2x)-5)(highlight(3x)+7),
highlight(6x^2),
(highlight(2x)-5)(3x+highlight(7)),
6x^2 + highlight(14x),
(3x -highlight(5))(highlight(3x)+7),
6x^2 + 14x - highlight(15x),
(2x -highlight(5))(3x+highlight(7)),
6x^2 + 14x - 15x - highlight(35),
6x^2 +highlight(14x) + highlight(-15x) - 35,
6x^2 - x - 35)}}}

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2x-5=0, then {{{highlight_green(x = 5/2)}}}
3x+7=0, then {{{highlight_green(x = - 7/3)}}}
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