Question 668682
y = mx + b
...
Given
b = {{{2/3}}}
x = 3
y = 0
...
solve for slope
0 = 3m + {{{2/3}}}
...
3m = {{{-2/3}}}
m = {{{(-2/cross(3))(cross(3))}}}
m = -2
...
{{{highlight(y = -2x + 2/3)}}}
...
{{{graph(300,200,-10,10,-10,10,-2x+(2/3))}}}
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