Question 668685
For sides a,b,c perimeter = a+b+c

Let a,b,c be the 1st,2nd,3rd sides respectively.

a = 2b - 65
c = b - 10

a+b+c = 2b -65 + b + b-10 = 165

4b = 240

b =  60

If b = 60 then:

a = 2(60) - 65 = 55

c = 60-10 = 50

So our sides are 55,60,50.