Question 668561
First off, what is cot(x)?  It is cos(x)/sin(x). We know that the arcos(cos(x)) = x.  While the arccos(sin(x)) = sqrt(1-x^2)  (think of pythagorean theorem with x, sqrt(1-x^2) and 1) So we have that arccos(cot(x)) =  x/sqrt(1-x^2)

When we consider that 5 is in radians, then we get that arccos(cot(x)) = 1.87, so it is slightly larger than pi/2 and thus in Q2.