<PRE><B>Question 668506</B>
Are you asking..
16x - 21
where x = {{{1/3}}}
...
{{{16(1/3) - 21 = 16/3 - 21}}}
Create common denominators
{{{16/3 - 21(3/3) = 16/3 - 63/3 = -47/3}}}
3 goes into 47 evenly 15 times, with 2 left over so,
15{{{2/3}}}
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