Question 668540
By our Triangle Angle-Sum Theorem, 4x+2y + 9y -2 + 10x+10 = 180

We also know that 9y -2 = 10x + 10, so solve for y.

9y = 10x + 12

y = (10x+12)/9

4x + 2(10x+12)/9 + 9(10x+12)/9 - 2  + 10x + 10 = 180

4x + (20/9)x + 24/9 + 10x + 12 -2 + 10x + 10 = 180

(236/9)x + 68/3 = 180

Multiply everything by 9 to get:

236x + 204 = 1620

236x = 1416

x = 6

10x + 10 = 9y-2

10(6) + 10 = 9y -2

72 = 9y

y = 8

So, angle A: 4(6) + 2(8) = 40

angle B: 9(8) -2 = 70

angle C:  10(6) + 10 = 70

40,70,70