Question 668486
Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(6)+-sqrt((6)^2-4(1)(34)))/(2(1))}}}


{{{x = (-6+-sqrt(36-(136)))/(2)}}}


{{{x = (-6+-sqrt(-100))/2}}}


{{{x = (-6+sqrt(-100))/2}}} or {{{x = (-6-sqrt(-100))/2}}}


{{{x = (-6+10*i)/2}}} or {{{x = (-6-10*i)/2}}}


{{{x = -3+5i}}} or {{{x = -3-5i}}}