Question 668448
Let n = number of nickles
Let q = number of quarters
To avoid decimals, work in cents not dollars.
The problem statement provides us we two equations:
(1) n + q = 36 and
(2) 5*n + 25*q = 460
To solve put n of (1) into (2) or
(3) 5*(36 - q) + 25*q = 460 or
(4) 180 - 5*q + 25*q = 460 or
(5) 20*q = 280 or
(6) q = 14 and from (1) we get
(7) n = 22
Are these correct? Check using (2).
Is (5*22 + 25*14 = 460)?
Is (110 + 350 = 460)?
Is (460 = 460)? Yes
Answer: Karla has 22 nickles and 14 quarters.