<PRE><B>Question 668333</B>
-------------- 	percent	----------------	Amount									
Alcohol I	50	----------------			16	ounces						
Alcohol II	45	----------------			x	ounces						
Mixture	49	----------------	16	+	x	ounces						
												
50	*	16	+	45	x	=	49	(	16	+	x	)
800	+	45	x	=	784	+	49	x				
45	x		-49	x	=	-800	+	784				
-4	x	=	-16									
/	-4											
x	=	4		ounces	Alcohol II							
												
m.ananth@hotmail.ca												
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