Question 668322
0 = 2x^2+4x-48

To find X intercept y=0

{{{2x^2+4x-48=0}}}

{{{2(x^2+2x-24)=0}}}

{{{2(x^2+6x-4x-24)=0}}}


{{{2(x(x+6)-4(x+6))=0}}}

{{{2(x+6)(x-4)=0}}}

(x+6)(x-4)=0

x=-6 OR x=4

X Intercepts are -6 & 4