Question 668330
1      	x	+	-3	y  	=	15				
Find the slope of this line										                                                                                                            
										
-3	y  	=	-1      	x	+	15    				
Divide by	-3									
	y  	=	  1/ 3	x	+	-5    				
Compare this equation with y=mx+b,					m= slope & b= y intercept					
slope m =	 1/3									
										
The slope of a line perpendicular to the above line will be the negative reciprocal										-3    
Because m1*m2 =-1										
The slope of the required line will be			-3    							
										
m=	-3    	,point	(	0	,	-4	)			
Find b by plugging the values of m & the point in										
y=mx+b										
-4	=	-0      	+	b						
b=	-4    									
m=	-3    									
The required equation is y  	=	-3      	x		-4  

y+3x=-4    			
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