Question 60474
y=x^2+x-6
The x-intercepts are the points where the parabola crosses the x-axis.  The values of y will always be zero.
.
y= x^2+x-6 [Factor]
y=(x-2)(x+3)
0=(x-2)(x+3) [Set each factor equal to zero and solve for x]
x-2=0
x=2
x-intercpet = (2, 0)
.
x+3=0
x=-3
The other x-intercept = (-3, 0)

{{{ graph( 300, 200, -6, 5, -10, 10, x^2+x-6) }}}