Question 668173
Use FOIL to solve/simplify/expand this. (First, Outer, Inner, Last)

That means you take {{{(x+3)(x+6)}}}

Then, you multiply the first, outer, inner, and then last numbers: {{{x^2+6x+3x+18}}}
(This is x times x plus x times six plus three times x plus three times six)
Combine like terms: {{{x^2+9x+18}}}

I hope this is what you were looking for.