Question 667915
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
degree 5 and zeros of –6, –2, 0, 2, and 6
  x(x -6)(x+6)(x-2)(x+2)= x(x^2-36)(x^2-4) = (x^3 - 36x)(x^2 - 4)
{{{(x^3 - 36x)(x^2 - 4)= x^5 - 4x^3 - 36x^3 + 144x = x^5 -40x^2 + 144x}}}