Question 667811
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Hi,
What weight{{{highlight(x)}}} of water must be added to 50 lb of a 36% sulfuric acid solution 
to yield a 20% solution? 
          WATER = WATER ( and...lbs the same on both sides of the EQ)
  x + .64*50lb = .80(50lb+x)
     .2x = .16*50lb
        x = 40lb of water must be added
and...
 {{{40lb + 32lb = 72 lb = .80* 90lb}}}