<PRE><B>Question 666574</B>
Is that 3{{{2/3}}} cups?
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Convert to improper fraction
3x3 = 9 + 2 = 11; so {{{3(2/3) = 11/3}}}
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{{{2(11/3) = 22/3}}}
Converting back to a mixed fraction
3 goes into 22, 7 times evenly, with 1 left over
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{{{highlight_green(7(1/3))}}}cups in the doubled recipe.
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Alternatively,
{{{3(2/3) + 3(2/3)  = 6(4/3) = 7(1/3)}}}
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