Question 667738
Establish the variables
x = tens place
y = ones place
...
Given
x = y+3
x+y = {{{1/7}}}(10x+y)
...
Substitute x into the equation
y+3 + y = {{{1/7}}}(10(y+3) + y)
...
Distribute the 10
2y + 3 = {{{1/7}}}(10y + 30 + y)
...
Combine like terms
2y + 3 = {{{1/7}}}(11y + 30)
...
Multiply both sides by 7 to be rid of the fraction
14y + 21 = 11y + 30
Isolate y
14y - 11y = 30 - 21
3y = 9
{{{highlight_green(y=3)}}}
...
x = y+3 = 3+3
{{{highlight_green(x=6)}}}
...
Then number is {{{highlight(63)}}}
...
Check {{{cartoon(
(1/7)*(63) = 9,
6+3=9)}}}
.....................
Delighted to help.
-Reading Boosters
Wanting for others what we want for ourselves.
www.MyHomeworkAnswers.com