Question 667680
{{{4x^2=324 }}}


Write the equation in standard form

{{{4x^2+0x+(-324)=0

a=4, b=0, c=-324

discriminant = {{{sqrt(b^2-4ac)}}}

D= 16*324
d=5184

d>0 so the roots are real 

{{{x1= (-b+sqrt(b^2-4ac))/2a}}}

= (0+72)/8
=9
{{{x2= (-b-sqrt(b^2-4ac))/2a}}}


x2=  (0-72)/8
-9

+9 & -9 are the roots of the equation