Question 667470
{{{h(k-2)= 3x^2-5x+1}}}
{{{h(k-2)= 3(k-2)^2-5(k-2)+1}}}
{{{h(k-2)= 3(k^2-4k+4)-5k+10+1}}}
{{{h(k-2)= 3k^2-12k+12-5k+11}}}
{{{h(k-2)= 3k^2-17k+23}}}
if h(K-2)=0 then:
{{{0= 3k^2-17k+23}}}
*[invoke quadratic "k", 3, -17, 23 ]