Question 667464
Simplify:      (2a^2–ab–3b^2)/(a^2-36b^2) ÷ (4a+4b)/(8a-48b)
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Invert the divisor and multiply
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= (2a^2–ab–3b^2)/(a^2-36b^2)*(8a - 48b)/(4a+4b)
Cancel factors of 4 
= (2a^2–ab–3b^2)/(a^2-36b^2)*(2a - 12b)/(a+b)
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Factor the 2 terms in (2a^2–ab–3b^2)/(a^2-36b^2)
See what you can do.