Question 667303
You probably know, that the graph for {{{y=x^3}}} is
{{{graph(300,300,-5,5,-5,5,x^3)}}},
and that the graph for the inverse function, {{{y=root(3,x)}}}, is
{{{graph(300,300,-5,5,-5,5,x^(1/3),-(-x)^(1/3))}}}.
Both graph are S-shaped, symmetrical about the middle point (0,0).
The graph for {{{y=root(3,x-1)}}} is similar, but shifted one unit to the right because that midpoint now happens when {{{x=1}}}. (At that point you still have {{{y=0}}}).
{{{graph(300,300,-5,5,-5,5,(x-1)^(1/3),-(1-x)^(1/3))}}}.
The graph for {{{y=root(3,x-1)+1}}} is  the same as for {{{y=root(3,x-1)}}}, but shifted one unit up:
{{{graph(300,300,-5,5,-5,5,(x-1)^(1/3)+1,-(1-x)^(1/3)+1)}}}.
The answer is {{{highlight(C)}}}.