Question 667358
Graph the function and state the vertex, the axis of symmetry, the intercepts if any.
F(x)=x²-4x+3 
What is the vertex?
What is the axis of symmetry?
What are the intercepts if any?
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F(x)=x²-4x+3
complete the square:
y=(x^2-4x+4)+3-4
y=(x-2)^2-1
This is an equation of a parabola that opens upwards.
Its standard form: y=A(x-h)^2+k, (h,k) =(x,y) coordinates of the vertex, A is a coefficient that affects the width of the curve.
..
For given parabola:y=(x-2)^2-1
vertex: (2,-1)
A=1
Axis of symmetry: x=2
x-intercepts
set y=0
(x-2)^2-1=0
(x-2)^2=1
x-2=±1
x=2±1
x=3 and 1
see graph below:
{{{ graph( 300, 300, -10, 10, -10, 10,(x-2)^2-1) }}}