<PRE><B>Question 667280</B>
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There are 3 face cards in each of 4 suits, so there are 12 face cards.  That means that there are 52 minus 12 non-face cards.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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