Question 667191
2^(4y+1)-3^y=0
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{{{2^(4y+1) = 3^y}}}
(4y+1)log(2) = y*log(3)
4y*log(2) + log(2) = y*log(3)
4y*log(2) - y*log(3) = -log(2)
y*log(16) - y*log(3) = - log(2)
y*(log(16) - log(3) = -log(2)
{{{y = log(2)/(log(3) - log(16))}}}
{{{y = log(2)/log(3/16)}}}
 =~ -0.41407