Question 667206
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Hi,Re TY
You did not say how You determine the P-value given the z-value
NORMSDIST(.6723) is one such way of doing that ...using an Excel function NORMSDIST.
Chart or TI calculator works as well.
&#956; = 22  ,  &#963; =11.9  and z = (30-22)/11.9
P(x>30) = 1 -P(z &#8804; .6723) = 1- NORMSDIST(.6723)= 1-.75 = .25