Question 667135
This is the right place
{{{ ( x^3 / 64 ) ^(2/3) }}}
{{{ ( x^3 / 4^3 ) ^(2/3) }}}
{{{ (((x/4)^3)^(1/3))^2 }}}
{{{ ( x/4 )^2 }}}
{{{ x^2 / 16 }}}