Question 667075
-------------- 	percent	----------------	Amount									
Sulphuric acid I	24	----------------			4	liters						
sulphuric acid II	40	----------------			x	liters						
Mixture	35	----------------	4	+	x	liters						
												
24*4+40	x=35(4+x)
96+40x	=140+35	x				
40x-35	x	=-96+140				
5x=44									
/	5											
x	=	8.8		liters	sulphuric acid II							
												
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