Question 666595
{{{logx9 + logx27 =5}}}
{{{logx3^2 + logx3^3 = 5}}}
{{{2logx3 + 3 logx3 = 5}}}
{{{5logx3 = 5}}}
{{{logx3 = 1}}}
By definition of logarithm, that simply says {{{x^1 = 3}}}
so x = 3