Question 666554
let the numbers be x & y x>y

x+y = 36


dividend = divisor * quotient + remainder

x= y*2+3
x-2y=3


x+y=36
x-2y=3

multiply first equation by 2 and add to the second

2x+2y=72
x-2y=3
3x=75
/3
x=25

plug value of x in 
x+y = 36
25+y=36
y=36-25
y=11

the numbers are 25 & 11