Question 666328
Let f(x) = {{{log(5,(x-1)+6)}}}

By definition, the x-intercept is the x value where y=0

So  {{{0=log(5,(x-1)+6)}}}
{{{ -6 = log(5,x-1)}}}

{{{5^-6 = 5^log(5,x-1)}}}
{{{5^-6 = x-1}}}
{{{(5^-6) + 1}}} = 1.000064