Question 60293
Er...not quite!
Let n = the number of nickels ($0.05) and d = the number of dimes ($0.10).
The sum of the nickels and dimes (coins) can be written:
1) n + d = 43
The total value of the coins can be written:
2) n($0.05) + d($0.10) = $3.40

This is the required system of two equations in two unknowns (n and d).

You can solve this system by substitution.
Solve equation 1) for n: (n = 43 - d) and substitute this into equation 2) then solve for d.

2a) (43-d)($0.05) + d($0.10) = $3.40 Simplify and solve for d.
2.15 - 0.05d + 0.10d = 3.40
2.15 + 0.05d = 3.40 Subtract 2.15 from both sides.
0.05d = 1.25 Divide both sides by 0.05
d = 25 There are 25 dimes.
n = 43 - d
n = 43 - 25
n = 18 There are 18 nickels.

Check:

n + d = 18 + 25 = 43

18($0.05) + 25($0.10) = $0.90 + $2.50 = $3.40