Question 666109
{{{((3x^2-13x+14)/(4x))  * (((12x^2)/(x^3-2x^2)) /((9x-21)/6)))}}}
So turn everything into multiplication by flipping (9x-21)/6


{{{((3x^2-13x+14)/(4x)) * ((12x^2)/(x^3-2x^2)) * (6/(9x-21))}}}

Now factor everything

{{{((x-2)(3x-7))/(4x)) * ((12*x^2)/(x^2(x-2))) * (6/(3*(3x-7))}}}

Combine numerator and denominators:

{{{((x-2)*(3x-7)*(12 *(x^2)*6))/(4x*x^2*(x-2)*3*(3x-7))}}}

Cancel stuff:

{{{(cross((x-2))*cross((3x-7))*(12cross(x^2))*6)/(4x*cross(x^2)*cross((x-2))*3*cross((3x-7)))}}}

So we're left with {{{(72)/(12x)}}}

Divide through the 12 into the 72 to get:

{{{6/x}}}