Question 665929
Starting with
{{{5x^2 + 2x = 3}}}
Set the equation equal to 0
{{{5x^2 + 2x - 3 = 0}}}
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Thinking of multiples of 3 and mutliples of 5 that will subtract to 2.
(x - )(x + ) mixed signs due to + 2 and -3
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(5x-3)(x+1)=0
Check with FOIL
{{{5x^2 + 5x - 3x - 3}}}
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(5x-3)(x+1)=0
5x-3=0, so x = {{{3/5}}}
x+1=0, so x = -1
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