Question 665894

I guess you have two problems even you marked only nubmer 1.

1. 

{{{sqrt(6)/9=sqrt(2*3)/3*3=sqrt(2*3)(1/3)/3=sqrt(2*3(1/9))/3=sqrt(2*cross(3)(1/cross(9)3))/3=sqrt(2/3)/3=0.27}}}

2.

{{{sqrt(10)/ (32x^5*y^5)}}}


{{{sqrt(10)/ (2*16x^5*y^5)}}}...move {{{2}}} from denominator in nominator


{{{sqrt(10)(1/2)/ (16x^5*y^5)}}}....put it under square root...


{{{sqrt(10*(1/4))/ (16x^5*y^5)}}}


{{{sqrt(10/4)/ (16x^5*y^5)}}}...simplify square root


{{{sqrt(cross(10)5/cross(4)2)/ (16x^5*y^5)}}}


{{{sqrt(5/2)/ (16x^5*y^5)}}}