Question 665795
given:

{{{f(x)=x^2-4x+8 }}}

in the form {{{f(x)=a(x-h)^2+k}}}

{{{f(x) = (x^2 - 4x) + 8}}}

{{{(x^2 - 4x - 4) + 8 - 4

{{{(x^2 - 4x - 2^2) + 4

{{{(x-2)^2 + 4}}}

the vertex:({{{2}}},{{{4}}})

{{{drawing(600,600,-10,10,-10,10,grid(1),circle(2,4,0.1),locate(2,4,"V(2,4)"),graph(600,600,-10,10,-10,10,(x-2)^2 + 4))}}}